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Solve this equation given below x-2y+z= -9 2y+3z= 16 4y=8
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? = 9, ? = 2, ? = - 4
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? = −9, ? = -2, ? = 4
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? = −9, ? = 2, ? = 4
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? = −9, ? = - 2, ? = - 4
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The given system of equations can be solved using the method of substitution. From the third equation, we can solve for y: y = 2. Substituting this value of y into the second equation, we can solve for z: 2(2) + 3z = 16, which gives z = 4. Substituting the values of y = 2 and z = 4 into the first equation, we can solve for x: x - 2(2) + 4 = -9, which gives x = -9. Therefore, the correct answer is ? = -9, ? = 2, ? = 4.